Confidence Intervals for the Mean

t Distribution

A t distribution has more scores in its tails and fewer in the center than a normal distribution, so it is leptokurtic. Also, a t distribution with 20 degrees of freedom has 95% of its distribution within 2.086 standard deviations of its mean.
As the degrees of freedom increase, the t distribution looks more and more like a normal distribution.
Use the "Find t for a confidence interval" calculator for a 90% confidence interval and you will get 1.753.
Use the "t distribution" calculator and enter 10 for df and 2 for t. You will see that the probability of getting something greater than 2 SDs from the mean is .0734, so the probability of getting something less than 2 SDs from the mean is 1 - .0734 = .9266.
There is a population of test scores with an unknown standard deviation. You sample 21 scores from this population, and you calculate the mean and standard deviation. You get a value for the mean that is 1.5 standard errors greater than what you think is the population mean. What is the probability that you would get a value 1.5 standard deviations or more from the mean in this t distribution? Answer: 0.148 or 14.8%

Callback before_footer in local_aigrade component should be migrated to new hook callback for core\hook\output\before_footer_html_generation

line 7225 of /lib/moodlelib.php: call to debugging()
line 7292 of /lib/moodlelib.php: call to {closure}()
line 71 of /lib/classes/hook/output/before_footer_html_generation.php: call to get_plugins_with_function()
line 987 of /lib/classes/output/core_renderer.php: call to core\hook\output\before_footer_html_generation->process_legacy_callbacks()
line 97 of /mod/book/tool/print/index.php: call to core\output\core_renderer->footer()